Comments on: What is the total distance travelled for an accelerating automobile? http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/ Mon, 21 May 2012 18:46:00 +0000 http://wordpress.org/?v=2.7 hourly 1 By: Examiner http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/comment-page-1/#comment-8558 Examiner Sun, 17 Jan 2010 17:21:31 +0000 http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/#comment-8558 First part : The vehicle will have a final speed of 2.6 x 18 m/s = 46.8m/s. The distance travelled will be the average speed x time = 46.8/2 x 18 = 421.2 metres. (the average speed will be how fast the vehicle is going at the half way point hence the division by 2) 2nd Part: The distance will be the speed x time = 46.8 x 15 = 702 metres. 3rd Part the time taken to stop will be the speed divided by the negative acceleration = 46.8/2.9 = 16.148 seconds. The distance travelled will again be the average speed x time = 46.8/2 x 16.148 = 377.86 metres. Total distance travelled is the three distances added together.<a href="http://www.bigguitarshop.com/other-stringed-instruments-84993"> Examiner</a> First part : The vehicle will have a final speed of 2.6 x 18 m/s = 46.8m/s. The distance travelled will be the average speed x time
= 46.8/2 x 18 = 421.2 metres. (the average speed will be how fast the vehicle is going at the half way point hence the division by 2)
2nd Part: The distance will be the speed x time = 46.8 x 15 = 702 metres.
3rd Part the time taken to stop will be the speed divided by the negative acceleration = 46.8/2.9 = 16.148 seconds. The distance travelled will again be the average speed x time = 46.8/2 x 16.148 = 377.86 metres.
Total distance travelled is the three distances added together. Examiner

]]> By: ANSHUL http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/comment-page-1/#comment-8557 ANSHUL Fri, 15 Jan 2010 07:57:07 +0000 http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/#comment-8557 Part I : The vehicle starts at zero velocity with acceleration 2.6m/s^2 so, s1=ut+1/2at^2 where u=0, s= 1/2*2.6*18*18=421.2m Part II : At the end of part I, the vehicles velocity is v=u+at (u=0) v=at=2.6*18=46.8m/s, now the vehicle is moving at a constant speed for 15sec, so distance(s2)=speed*time=2.6*18*15=702m. Part III : Now the vehicle decelerates at -2.9m/s^2, and stops so final velocity is zero and initial velocity is 46.8m/s as found in part II. v^2=u^2+2as, where v=0 and a will be negative for deceleration. s3=46.8^2/2*2.9m add the three distances, u get the total distance traveled by the vehicle.<a href="http://www.premierhomestyle.com/towel-bars-and-rings-1543"> ANSHUL</a> Part I : The vehicle starts at zero velocity with acceleration 2.6m/s^2
so, s1=ut+1/2at^2 where u=0, s= 1/2*2.6*18*18=421.2m

Part II : At the end of part I, the vehicles velocity is v=u+at (u=0)
v=at=2.6*18=46.8m/s, now the vehicle is moving at a constant speed for 15sec, so distance(s2)=speed*time=2.6*18*15=702m.

Part III : Now the vehicle decelerates at -2.9m/s^2, and stops so final velocity is zero and initial velocity is 46.8m/s as found in part II.
v^2=u^2+2as, where v=0 and a will be negative for deceleration.
s3=46.8^2/2*2.9m

add the three distances, u get the total distance traveled by the vehicle. ANSHUL

]]> By: Inviz http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/comment-page-1/#comment-8556 Inviz Thu, 14 Jan 2010 07:32:55 +0000 http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/#comment-8556 Ok, iam assuming you know the equations of motion: v= u + at s=ut + 0.5at^2 v^2=u^2 + 2as s=((u+v)/2)t We need to break this motion up into seperate sections. Note however that all the units in this question are in SI units, so they are consistent with each other. You don't have kilometres which you would need to convert into metres for example, before using these equations. In that case I won't put in the units by the numbers in my calculations everytime, just to make it look clearer. But they are there and they are consistent. First section is from rest (u=0) accelerating at 2.6m/s^2 for 18s. We will find the displacement travelled here. We know u(initial velocity)=0, we know a(acceleration)= 2.6 and t=18 and we want s(displacement) the equation connecting these four is s=ut + 0.5at^2 (we don't need v and this equation does not have v) so s = (0 x 18) + (0.5 x 2.6 x 18^2) = 421.2m <a href="http://www.businessbrokersguide.com/miami-business-broker.htm"> Inviz</a> Ok, iam assuming you know the equations of motion:
v= u + at
s=ut + 0.5at^2
v^2=u^2 + 2as
s=((u+v)/2)t

We need to break this motion up into seperate sections.

Note however that all the units in this question are in SI units, so they are consistent with each other. You don’t have kilometres which you would need to convert into metres for example, before using these equations. In that case I won’t put in the units by the numbers in my calculations everytime, just to make it look clearer. But they are there and they are consistent.

First section is from rest (u=0) accelerating at 2.6m/s^2 for 18s. We will find the displacement travelled here.

We know u(initial velocity)=0, we know a(acceleration)= 2.6 and t=18 and we want s(displacement)

the equation connecting these four is s=ut + 0.5at^2
(we don’t need v and this equation does not have v)

so s = (0 x 18) + (0.5 x 2.6 x 18^2)
= 421.2m Inviz

]]> By: behroz_ahmedali http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/comment-page-1/#comment-8555 behroz_ahmedali Tue, 12 Jan 2010 08:37:01 +0000 http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/#comment-8555 The first distance distance = average velocity *time Average velocity= (initial velocity+Final velocity)/2 distance = ((0m/s + 2.6m/s)/2)*18s= 23.4m 2nd distance = average velocity * time 2nd distance = 2.6m/s * 15s = 39m 3rd distance Initial velocity=2.6m/s Final velocity=0m/s acceleration= -2.9m/s^2 3rd distance = average velocity * time average velocity = ((initial velocity + final velocity)/2) time=(final velocity - initial velocity)/acceleration 3rd distance = ((2.6m/s+0m/s)/2) * (0m/s - 2.6m/s)/-2.9m/s^2 3rd distance = (1.3m/s)*(0.897s) =1.17m add the three distance<a href="http://www.cargearusa.com/srch/srch.php?q=Mercury"> behroz_ahmedali</a> The first distance

distance = average velocity *time

Average velocity= (initial velocity+Final velocity)/2

distance = ((0m/s + 2.6m/s)/2)*18s= 23.4m

2nd distance = average velocity * time
2nd distance = 2.6m/s * 15s = 39m

3rd distance
Initial velocity=2.6m/s
Final velocity=0m/s
acceleration= -2.9m/s^2

3rd distance = average velocity * time
average velocity = ((initial velocity + final velocity)/2)
time=(final velocity - initial velocity)/acceleration

3rd distance = ((2.6m/s+0m/s)/2) * (0m/s - 2.6m/s)/-2.9m/s^2
3rd distance = (1.3m/s)*(0.897s) =1.17m

add the three distance behroz_ahmedali

]]> By: Xopher http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/comment-page-1/#comment-8554 Xopher Mon, 11 Jan 2010 05:49:52 +0000 http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/#comment-8554 x (distance) T = Time A = Acceleration u = uniform speed x = ut+1/2ATx2 That should be all you need without me giving it to you :_)<a href="http://www.besthomeorganizers.com/644"> Xopher</a> x (distance)
T = Time
A = Acceleration
u = uniform speed

x = ut+1/2ATx2

That should be all you need without me giving it to you :_) Xopher

]]> By: Johnny http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/comment-page-1/#comment-8553 Johnny Sun, 10 Jan 2010 22:17:17 +0000 http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/#comment-8553 R X T = D rate times time equals distance. you can do it!<a href="http://www.resumeminers.com/universities/journalism-degree.htm"> Johnny</a> R X T = D

rate times time equals distance.
you can do it! Johnny

]]> By: freckles http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/comment-page-1/#comment-8552 freckles Sat, 09 Jan 2010 00:12:25 +0000 http://www.cargearusa.com/blog/what-is-the-total-distance-travelled-for-an-accelerating-automobile/#comment-8552 I dunno! just as long as richie hammond is ok!<a href="http://www.greattoolsusa.com/sanders-4380"> freckles</a> I dunno!

just as long as richie hammond is ok! freckles

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