<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
	>
<channel>
	<title>Comments on: Two cars start traveling toward each other at the same time from positions 480 kilometers apart?</title>
	<atom:link href="http://www.cargearusa.com/blog/two-cars-start-traveling-toward-each-other-at-the-same-time-from-positions-480-kilometers-apart/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.cargearusa.com/blog/two-cars-start-traveling-toward-each-other-at-the-same-time-from-positions-480-kilometers-apart/</link>
	<description></description>
	<pubDate>Mon, 21 May 2012 17:15:59 +0000</pubDate>
	<generator>http://wordpress.org/?v=2.7</generator>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<xhtml:meta xmlns:xhtml="http://www.w3.org/1999/xhtml" name="robots" content="noindex" />
	<item>
		<title>By: Jessica</title>
		<link>http://www.cargearusa.com/blog/two-cars-start-traveling-toward-each-other-at-the-same-time-from-positions-480-kilometers-apart/comment-page-1/#comment-7743</link>
		<dc:creator>Jessica</dc:creator>
		<pubDate>Sat, 19 Sep 2009 15:24:15 +0000</pubDate>
		<guid isPermaLink="false">http://www.cargearusa.com/blog/two-cars-start-traveling-toward-each-other-at-the-same-time-from-positions-480-kilometers-apart/#comment-7743</guid>
		<description>Let AB = 480 kms and car P starts from A &#038; car Q starts from B.

Let at point M both car meet, so 
AM = 4v............(v is the speed of car P)

BM = 4(v + 40)............(v+40 is the speed of car Q

As AM + MB = 480,

4v + 4(v + 40) = 480
8v + 160 = 480
8v = 320
v = 40,,,,,,,,,Speed of car P

v + 40 = 40 + 40 = 80.......Speed of car Q</description>
		<content:encoded><![CDATA[<p>Let AB = 480 kms and car P starts from A &#038; car Q starts from B.</p>
<p>Let at point M both car meet, so<br />
AM = 4v&#8230;&#8230;&#8230;&#8230;(v is the speed of car P)</p>
<p>BM = 4(v + 40)&#8230;&#8230;&#8230;&#8230;(v+40 is the speed of car Q</p>
<p>As AM + MB = 480,</p>
<p>4v + 4(v + 40) = 480<br />
8v + 160 = 480<br />
8v = 320<br />
v = 40,,,,,,,,,Speed of car P</p>
<p>v + 40 = 40 + 40 = 80&#8230;&#8230;.Speed of car Q</p>
]]></content:encoded>
	</item>
</channel>
</rss>

