Suppose an automobile has 3300 J of kinetic energy. When it moves at twice the speed, what will be its kinetic?


automobile
Hghsd asked:


Suppose an automobile has 3300 J of kinetic energy. When it moves at twice the speed, what will be its kinetic energy?

What’s its kinetic energy at three times the speed?

This entry was posted on Sunday, January 10th, 2010 at 6:59 am and is filed under Physics. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

5 Responses to “Suppose an automobile has 3300 J of kinetic energy. When it moves at twice the speed, what will be its kinetic?”

  1. kasab Says:

    Four times for twice the speed.
    Nine times for three times the speed.
    Since, kinetic energy =1/2*mv²,Then, velocity is increased “m” times kinetic energy becomes “m²” times kasab

  2. Polyhymnio Says:

    KE is proportional to the square of the velocity, therefore if the speed is doubled, the KE is increased by a factor of four. 13200 J Polyhymnio

  3. lucky me Says:

    kinetic energy depends on mass and square of the velocity

    so When it moves at twice the speed its kinetic energy will become 4 times the 1st one
    i.e. 13200J

    and its kinetic energy at three times the speed will be three times the 1st one
    ie19800J

    ………………., lucky me

  4. Johnny Y Says:

    The first poster is correct. Here’s why:

    Kinetic energy of an object is equal to K = .5mv^2, where m is mass and v is velocity.

    If you assume that originally, the automobile is moving at 1v, K = 3300 J, or

    K = 3300 J = .5m(1v)^2 = .5mv^2

    If you double the speed, or make the automobile travel at 2v,

    K = .5m(2v)^2 = .5m4v^2 = 2mv^2

    This is FOUR times as much as when the automobile traveled at 1v. Therefore, the automobile will have 4*3300 = 13200 J of kinetic energy. If the automobile moves at 3v,

    K = .5m(3v)^2 = .5m9v^2 = 4.5mv^2

    That’s NINE times as much as when the automobile traveled at 1v. Therefore, the automobile will have 9*3300 = 29700 J of kinetic energy.

    Sure, it’s useful to know the answer, but what’s more important is to know the METHOD behind it.

    Hope this helps! Johnny Y

  5. Sniper Says:

    The kinetic energy =1/2*mv².
    So when velocity is increased ‘n’ times kinetic energy becomes n² times
    When the auto moves twice the speed KE is quadrupled and when it moves at thrice the speed it is 9KE Sniper

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