How much time is required for the entering car to catch up with the other car?


car
Mariah asked:


A race driver has made a pit stop to refuel. After refueling, he starts from rest and leaves the pit area with an acceleration whose magnitude is 5.4 m/s2; after 3.8 s he enters the main speedway. At the same instant, another car on the speedway and traveling at a constant velocity of 68.9 m/s overtakes and passes the entering car. The entering car maintains its acceleration. How much time is required for the entering car to catch up with the other car?

This entry was posted on Saturday, July 17th, 2010 at 1:05 pm and is filed under Physics. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

One Response to “How much time is required for the entering car to catch up with the other car?”

  1. Jim Says:

    t = time to catch up
    constant speed car distance traveled in (t) = 68.9t
    velocity of accelerating car at main speedway entrance = (3.8)(5.4) = 20.5 m/s
    accelerating car distance traveled in (t) = Vi(t) + 1/2(5.4)t² = 20.5t + 2.7t²

    set distances traveled by the two cars equal
    68.9t = 20.5t + 2.7t²
    cancel t’s
    68.9 = 20.5 + 2.7t
    2.7t = 68.9 - 20.5 = 48.4
    t = 48.4/2.7 = 17.9 s ANS Jim

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