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	<title>Comments on: How do police determine how fast a car had been traveling after an accident has occurred?</title>
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	<link>http://www.cargearusa.com/blog/how-do-police-determine-how-fast-a-car-had-been-traveling-after-an-accident-has-occurred/</link>
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	<pubDate>Fri, 18 May 2012 01:53:39 +0000</pubDate>
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		<title>By: Ted</title>
		<link>http://www.cargearusa.com/blog/how-do-police-determine-how-fast-a-car-had-been-traveling-after-an-accident-has-occurred/comment-page-1/#comment-7262</link>
		<dc:creator>Ted</dc:creator>
		<pubDate>Mon, 17 Aug 2009 07:00:20 +0000</pubDate>
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		<description>Simply plug the numbers into the equation and solve or rearrange the equation first.

55=2 sqr 5L        divide by 2
27.5=sqr5L           square both sides
756.25 = 5L         divide by 5
L = 151.25   at 55mph

or rearrange the equation r^2=4(5L)=20L
    L= r^2 / 20 
   L = 90^2 / 20 = 405  at 90 mph</description>
		<content:encoded><![CDATA[<p>Simply plug the numbers into the equation and solve or rearrange the equation first.</p>
<p>55=2 sqr 5L        divide by 2<br />
27.5=sqr5L           square both sides<br />
756.25 = 5L         divide by 5<br />
L = 151.25   at 55mph</p>
<p>or rearrange the equation r^2=4(5L)=20L<br />
    L= r^2 / 20<br />
   L = 90^2 / 20 = 405  at 90 mph</p>
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